Menu
I tried the following line:
static const const char* values[];
But I get the following warning on VC++ warning C4114:
same type qualifier used more than once.
What is the correct declaration? The goal is to create an immutable array of c strings.
213
const char* is a pointer to a constant char, meaning the char in question can't be modified. char* const is a constant pointer to a char, meaning the char can be modified, but the pointer can not (e.g. you can't make it point somewhere else).
In C programming language, *p represents the value stored in a pointer and p represents the address of the value, is referred as a pointer. const char* and char const* says that the pointer can point to a constant char and value of char pointed by this pointer cannot be changed.
The const char *Str tells the compiler that the DATA the pointer points too is const . This means, Str can be changed within Func, but *Str cannot. As a copy of the pointer is passed to Func, any changes made to Str are not seen by main....
Arrays are Not Constants It does NOT define a constant array. It defines a constant reference to an array. Because of this, we can still change the elements of a constant array.
You wrote const const instead of static const char* const values[]; (where you define the pointer and the underlying values as const)
Also, you need to initialize it:
static const char* const values[] = {"string one", "string two"};
131
Try
static const char* const values[];
The idea is to put the two consts on either side of *: the left belongs to char (constant character), the right belongs to char* (constant pointer-to-character)
5
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With
