Just wondering if there is anyway to represent the following code in C# 3.5:
public struct Foo<T> {
public Foo(T item) {
this.Item = item;
}
public T Item { get; set; }
public static explicit operator Foo<U> ( Foo<T> a )
where U : T {
return new Foo<U>((U)a.Item)
}
}
Thanks
&n writes the address of n . The address of a variable points to the value of that variable.
Description. In the C Programming Language, the #if directive allows for conditional compilation. The preprocessor evaluates an expression provided with the #if directive to determine if the subsequent code should be included in the compilation process.
Most compilers for C and C++ are written in C and C++. This is possible because of compiler bootstrapping.
'0' in any case is considered as false value, so when you pass 0 as an argument like: if(0) { ---statments--- } The statement part of will not get executed, and the system will directly jump to else part.
Conversion operators can't be generic. From the spec section 10.10, here's the format of a conversion-operator-declarator:
conversion-operator-declarator: implicit operator type ( type identifier ) explicit operator type ( type identifier )
Compare this with, say, a method-header:
method-header: attributesopt method-modifiersopt partialopt return-type member-name type-parameter-listopt ( formal-parameter-listopt ) type-parameter-constraints-clausesopt
(Sorry about the formatting - not sure how to do it better.)
Note that the operator format doesn't include a type parameter list or type parameter constraints.
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