Here is the code:
struct foo {
template<typename T = void>
friend foo f() { return {}; }
};
int main() {
auto x = f(); // clang++ can't find it, g++ can.
}
clang++ 3.4 gives:
fni2.cpp:8:12: error: use of undeclared identifier 'f'
auto x = f(); // clang++ can't find it, g++ can.
^
1 error generated.
g++ 4.9.0 compiles it, but I don't think it should have. This is a related question, but there was no definitive answer. Section 15.4.2/2,4 discuss this, but neither of them say anything to suggest that friend function templates defined in-class should have different visibility from non-template friend functions defined in-class.
This is of academic interest to me only, though it did arise from a question by someone else who may have had an actual use case.
It looks like a g++ bug to me.
Yes, this is an error. I'm surprised it's finding the function. Apparently GCC fails entirely to hide function templates.
This C++03 example also compiles, so it could be a regression:
struct foo {
template<typename T >
friend void f( T ) { }
};
int main() {
f( 3 ); // clang++ can't find it, g++ can.
}
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