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Is there a construct in C# which allows you to create a anonymous class implementing an interface, just like in Java?
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No, anonymous types cannot implement an interface. We need to create your own type. Anonymous types provide a convenient way to encapsulate a set of read-only properties into a single object without having to explicitly define a type first.
An anonymous class cannot access local variables in its enclosing scope that are not declared as final or effectively final. Like a nested class, a declaration of a type (such as a variable) in an anonymous class shadows any other declarations in the enclosing scope that have the same name.
An interface can't be instantiated directly. Its members are implemented by any class or struct that implements the interface. A class or struct can implement multiple interfaces.
As has already been stated, no, this is not possible. However, you can make a class that implements the desired interface and accepts a lambda in it's constructor so that you can turn a lambda into a class that implements the interface. Example:
public class LambdaComparer<T> : IEqualityComparer<T> { private readonly Func<T, T, bool> _lambdaComparer; private readonly Func<T, int> _lambdaHash; public LambdaComparer(Func<T, T, bool> lambdaComparer) : this(lambdaComparer, EqualityComparer<T>.Default.GetHashCode) { } public LambdaComparer(Func<T, T, bool> lambdaComparer, Func<T, int> lambdaHash) { if (lambdaComparer == null) throw new ArgumentNullException("lambdaComparer"); if (lambdaHash == null) throw new ArgumentNullException("lambdaHash"); _lambdaComparer = lambdaComparer; _lambdaHash = lambdaHash; } public bool Equals(T x, T y) { return _lambdaComparer(x, y); } public int GetHashCode(T obj) { return _lambdaHash(obj); } } Usage (obviously doing nothing helpful, but you get the idea)
var list = new List<string>() { "a", "c", "a", "F", "A" }; list.Distinct(new LambdaComparer<string>((a,b) => a == b)); No. C# doesn't support anonymous classes (except anonymous types which can't define methods).
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