Interface-implementing anonymous class in C#? [duplicate]

Question

Is there a construct in C# which allows you to create a anonymous class implementing an interface, just like in Java?

Answer 1

As has already been stated, no, this is not possible. However, you can make a class that implements the desired interface and accepts a lambda in it's constructor so that you can turn a lambda into a class that implements the interface. Example:

public class LambdaComparer<T> : IEqualityComparer<T> {     private readonly Func<T, T, bool> _lambdaComparer;     private readonly Func<T, int> _lambdaHash;      public LambdaComparer(Func<T, T, bool> lambdaComparer) :         this(lambdaComparer, EqualityComparer<T>.Default.GetHashCode)     {     }      public LambdaComparer(Func<T, T, bool> lambdaComparer,         Func<T, int> lambdaHash)     {         if (lambdaComparer == null)             throw new ArgumentNullException("lambdaComparer");         if (lambdaHash == null)             throw new ArgumentNullException("lambdaHash");          _lambdaComparer = lambdaComparer;         _lambdaHash = lambdaHash;     }      public bool Equals(T x, T y)     {         return _lambdaComparer(x, y);     }      public int GetHashCode(T obj)     {         return _lambdaHash(obj);     } } 

Usage (obviously doing nothing helpful, but you get the idea)

var list = new List<string>() { "a", "c", "a", "F", "A" }; list.Distinct(new LambdaComparer<string>((a,b) => a == b)); 

Answer 2

No. C# doesn't support anonymous classes (except anonymous types which can't define methods).