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I want a 20 character NULL('\0') terminating string filled with white spaces.
Currently I am doing it in following way
char foo[20];
for (i = 0; i < num_space_req; i++) //num_space_req < 20
{
foo[i] = ' ';
}
foo[num_space_req] = '\0';
Is there a better way for above?
861
You can initialize a one-dimensional character array by specifying: A brace-enclosed comma-separated list of constants, each of which can be contained in a character. A string constant (braces surrounding the constant are optional)
You can't initialise a char array with NULL , arrays can never be NULL . You seem to be mixing up pointers and arrays. A pointer could be initialised with NULL . char str[5] = {0};
Initializing Char Array A char array can be initialized by conferring to it a default size. char [] JavaCharArray = new char [ 4 ];
Initializing array with a string (Method 1):char arr[] = {'c','o','d','e','\0'}; In the above declaration/initialization, we have initialized array with a series of character followed by a '\0' (null) byte. The null byte is required as a terminating byte when string is read as a whole.
std::string foo(num_space_req,' ');
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