Initialize char array in C

Question

I am not sure what will be in the char array after initialization in the following way:

char buf[5]={0,};

Is that equivalent to

char buf[5]={0,0,0,0,0};

Answer 1

Yes, it is the same. If there are less number of initializers than the elements in the array, then the remaining elements will be initialized as if the objects having static storage duration, (i.e., with 0).

So,

char buf[5]={0,};

is equivalent to

 char buf[5]={0,0,0,0,0};

Related Reading : From the C11 standard document, chapter 6.7.9, initalization,

If there are fewer initializers in a brace-enclosed list than there are elements or members of an aggregate, or fewer characters in a string literal used to initialize an array of known size than there are elements in the array, the remainder of the aggregate shall be initialized implicitly the same as objects that have static storage duration.

Answer 2

Yes when you initialize one element in the array to 0 the rest are set to 0

char buf[5] = {0};

char buf[5] = "";

Both are same