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The two characters )" terminate the raw string literal in the example below.
The sequence )" could appear in my text at some point, and I want the string to continue even if this sequence is found within it.
R"( Some Text)" )"; // ^^ How can I include the sequence )" within the string literal without terminating it?
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Raw String Literal in C++ A Literal is a constant variable whose value does not change during the lifetime of the program. Whereas, a raw string literal is a string in which the escape characters like ' \n, \t, or \” ' of C++ are not processed. Hence, a raw string literal that starts with R”( and ends in )”.
Python raw string is created by prefixing a string literal with 'r' or 'R'. Python raw string treats backslash (\) as a literal character. This is useful when we want to have a string that contains backslash and don't want it to be treated as an escape character.
A string literal is a sequence of zero or more characters enclosed within single quotation marks. The following are examples of string literals: 'Hello, world!' 'He said, "Take it or leave it."'
String literals A string literal represents a string constant obtained from concatenating a sequence of characters. There are two forms: raw string literals and interpreted string literals. Raw string literals are character sequences between back quotes, as in `foo` .
Raw string literals let you specify an almost arbitrary* delimiter:
//choose ### as the delimiter so only )###" ends the string R"###( Some Text)" )###"; *The exact rules are: "any member of the basic source character set except: space, the left parenthesis (, the right parenthesis ), the backslash \, and the control characters representing horizontal tab, vertical tab, form feed, and newline" (N3936 §2.14.5 [lex.string] grammar) and "at most 16 characters" (§2.14.5/2)
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