I've found numerous examples of how to match and update an entire list with one pattern and one replacement, but what I am looking for now is a way to do this for multiple patterns and multiple replacements in a single statement or loop.
Example:
> print(recs)
phonenumber amount
1 5345091 200
2 5386052 200
3 5413949 600
4 7420155 700
5 7992284 600
I would like to insert a new column called 'service_provider' with /^5/ as Company1 and /^7/ as Company2.
I can do this with the following two lines of R:
recs$service_provider[grepl("^5", recs$phonenumber)]<-"Company1"
recs$service_provider[grepl("^7", recs$phonenumber)]<-"Company2"
Then I get:
phonenumber amount service_provider
1 5345091 200 Company1
2 5386052 200 Company1
3 5413949 600 Company1
4 7420155 700 Company2
5 7992284 600 Company2
I'd like to provide a list, rather than discrete set of grepl's so it is easier to keep country specific information in one place, and all the programming logic in another.
thisPhoneCompanies<-list(c('^5','Company1'),c('^7','Company2'))
In other languages I would use a for loop on on the Phone Company list
For every row in thisPhoneCompanies
Add service provider to matched entries in recs (such as the grepl statement)
end loop
But I understand that isn't the way to do it in R.
Using stringi
:
library(stringi)
recs$service_provider <- stri_replace_all_regex(str = recs$phonenumber,
pattern = c('^5.*','^7.*'),
replacement = c('Company1', 'Company2'),
vectorize_all = FALSE)
recs
# phonenumber amount service_provider
# 1 5345091 200 Company1
# 2 5386052 200 Company1
# 3 5413949 600 Company1
# 4 7420155 700 Company2
# 5 7992284 600 Company2
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