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In class object, how to auto update attributes?

I have a class which has multiple attributes that are related, for example:

class SomeClass:
    def __init__(self, n=0):
        self.list = range(n)
        self.listsquare = [ x**2 for x in self.list ]

If I make an object normally that would no problem, with

a = SomeClass(10)

I will get 2 lists, a.list and a.listsquare.

Now if I want to make a empty object first, and assign one attribute to it, I want the other attributes to be automatically updated, for example if I do

b = SomeClass()
b.list = range(5,10)

I want b.listsquare to be automatically updated, and also the other way around (assign b.listsquare and auto update b.list). Is this possible? Is Class the right choice for this?


Thanks to you all, but I'm completely overwhelmed by all the different answers. Can anyone give a complete solution so I can learn write my own?

I would like to achieve a class Foo with 3 attributes length, list and listsquare such that:

  1. If I do a = Foo(3), I get a.length = 3, a.list = [0, 1, 2], a.listsquare = [0, 1, 4].
  2. If I do b = Foo().list = [5, 6], I get b.length = 2, b.listsquare = [25, 36].
  3. If I do c = Foo().listsquare = [4, 9], I get c.length = 2, c.list = [2, 3].
like image 766
LWZ Avatar asked Feb 16 '13 23:02

LWZ


1 Answers

if updating one property due to an update on another property is what you're looking for (instead of recomputing the value of the downstream property on access) use property setters:

class SomeClass(object):
    def __init__(self, n):
        self.list = range(0, n)

    @property
    def list(self):
        return self._list
    @list.setter
    def list(self, val):
        self._list = val
        self._listsquare = [x**2 for x in self._list ]

    @property
    def listsquare(self):
        return self._listsquare
    @listsquare.setter
    def listsquare(self, val):
        self.list = [int(pow(x, 0.5)) for x in val]

>>> c = SomeClass(5)
>>> c.listsquare
[0, 1, 4, 9, 16]
>>> c.list
[0, 1, 2, 3, 4]
>>> c.list = range(0,6)
>>> c.list
[0, 1, 2, 3, 4, 5]
>>> c.listsquare
[0, 1, 4, 9, 16, 25]
>>> c.listsquare = [x**2 for x in range(0,10)]
>>> c.list
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
like image 83
Ali-Akber Saifee Avatar answered Sep 18 '22 18:09

Ali-Akber Saifee