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Ignore DTD specification in scala

Tags:

xml

scala

dtd

I'd like to occasionally ignore the dtd specification while parsing an xml file using Scala. I know that this can be done pretty easily with the java interface by doing

DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();

dbf.setValidating(false);
dbf.setFeature("http://xml.org/sax/features/namespaces", false);
dbf.setFeature("http://xml.org/sax/features/validation", false);
dbf.setFeature("http://apache.org/xml/features/nonvalidating/load-dtd-grammar", false);
dbf.setFeature("http://apache.org/xml/features/nonvalidating/load-external-dtd", false);

However, I'm not sure of how to do this easily with Scala's xml library. If possible i'd like to continue using the scala xml library as it's significantly better.

Thanks in advance!

like image 347
fozziethebeat Avatar asked Jul 03 '12 16:07

fozziethebeat


1 Answers

This works for me, but it depends on the implementation of the XML parser.

import scala.xml.Elem
import scala.xml.factory.XMLLoader
import javax.xml.parsers.SAXParser
object MyXML extends XMLLoader[Elem] {
  override def parser: SAXParser = {
    val f = javax.xml.parsers.SAXParserFactory.newInstance()
    f.setNamespaceAware(false)
    f.setFeature("http://apache.org/xml/features/disallow-doctype-decl", true);
    f.newSAXParser()
  }
}

See also this question, which is really your question but worded in a hostile way.

like image 135
Daniel C. Sobral Avatar answered Sep 19 '22 18:09

Daniel C. Sobral