if variable contains [duplicate]

Question

You might want indexOf

if (code.indexOf("ST1") >= 0) { ... }
else if (code.indexOf("ST2") >= 0) { ... }

It checks if contains is anywhere in the string variable code. This requires code to be a string. If you want this solution to be case-insensitive you have to change the case to all the same with either String.toLowerCase() or String.toUpperCase().

You could also work with a switch statement like

switch (true) {
    case (code.indexOf('ST1') >= 0):
        document.write('code contains "ST1"');
        break;
    case (code.indexOf('ST2') >= 0):
        document.write('code contains "ST2"');        
        break;        
    case (code.indexOf('ST3') >= 0):
        document.write('code contains "ST3"');
        break;        
    }​

You can use a regex:

if (/ST1/i.test(code))

The fastest way to check if a string contains another string is using indexOf:

if (code.indexOf('ST1') !== -1) {
    // string code has "ST1" in it
} else {
    // string code does not have "ST1" in it
}

if (code.indexOf("ST1")>=0) { location = "stoke central"; }

If you have a lot of these to check you might want to store a list of the mappings and just loop over that, instead of having a bunch of if/else statements. Something like:

var CODE_TO_LOCATION = {
  'ST1': 'stoke central',
  'ST2': 'stoke north',
  // ...
};

function getLocation(text) {
  for (var code in CODE_TO_LOCATION) {
    if (text.indexOf(code) != -1) {
      return CODE_TO_LOCATION[code];
    }
  }
  return null;
}

This way you can easily add more code/location mappings. And if you want to handle more than one location you could just build up an array of locations in the function instead of just returning the first one you find.