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I think this is a simple question, but I'm struggling with the following. In my example I have the following statement (language is C):
int foobar if (foobar) { // do something. } Now, if I am correct about this, this statement is true when foobar is not zero. So it should be much the same as if (foobar!=0).
But what happens if foobar becomes a negative number?
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The reason you get cannot convert an int to boolean is that Java expects a boolean in the if(...) construct - but menuNumber is an int . The expression menuNumber == 1 returns a boolean, which is what is needed. It's a common mix-up in various languages.
To check if a String contains digit character which represent an integer, you can use Integer. parseInt() . To check if a double contains a value which can be an integer, you can use Math. floor() or Math.
if (score >= 90) grade = 'A'; The following example displays Number is positive if the value of number is greater than or equal to 0 . If the value of number is less than 0 , it displays Number is negative .
negative or positive. Anything that's not a 0 is a true value in if
Also, Consider a negative number: -1
-1 in C internally is represented as: 0xFFFFFFFF, in which case, it would be a positive number if I cast it to unsigned integer.
But after the advent of C99 standard compilers, I suggest you use <stdbool.h> instead. Makes the guessing work a lot less:
Read here about stdbool.h
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