HttpServletRequest to complete URL

Question

I have an HttpServletRequest object.

How do I get the complete and exact URL that caused this call to arrive at my servlet?

Or at least as accurately as possible, as there are perhaps things that can be regenerated (the order of the parameters, perhaps).

Answer 1

The HttpServletRequest has the following methods:

• getRequestURL() - returns the part of the full URL before query string separator character ?
• getQueryString() - returns the part of the full URL after query string separator character ?

So, to get the full URL, just do:

public static String getFullURL(HttpServletRequest request) {     StringBuilder requestURL = new StringBuilder(request.getRequestURL().toString());     String queryString = request.getQueryString();      if (queryString == null) {         return requestURL.toString();     } else {         return requestURL.append('?').append(queryString).toString();     } } 

Answer 2

I use this method:

public static String getURL(HttpServletRequest req) {      String scheme = req.getScheme();             // http     String serverName = req.getServerName();     // hostname.com     int serverPort = req.getServerPort();        // 80     String contextPath = req.getContextPath();   // /mywebapp     String servletPath = req.getServletPath();   // /servlet/MyServlet     String pathInfo = req.getPathInfo();         // /a/b;c=123     String queryString = req.getQueryString();          // d=789      // Reconstruct original requesting URL     StringBuilder url = new StringBuilder();     url.append(scheme).append("://").append(serverName);      if (serverPort != 80 && serverPort != 443) {         url.append(":").append(serverPort);     }      url.append(contextPath).append(servletPath);      if (pathInfo != null) {         url.append(pathInfo);     }     if (queryString != null) {         url.append("?").append(queryString);     }     return url.toString(); }