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HTTP requests and JSON parsing in Python

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How get JSON data from GET request in Python?

To request JSON from a URL using Python, you need to send an HTTP GET request to the server and provide the Accept: application/json request header with your request. The Accept header tells the server that our Python client is expecting JSON.

How do you parse a JSON in Python?

Parse JSON - Convert from JSON to Python If you have a JSON string, you can parse it by using the json. loads() method. The result will be a Python dictionary.

How do you create a JSON request in Python?

To post a JSON to the server using Python Requests Library, call the requests. post() method and pass the target URL as the first parameter and the JSON data with the json= parameter. The json= parameter takes a dictionary and automatically converts it to a JSON string.


I recommend using the awesome requests library:

import requests

url = 'http://maps.googleapis.com/maps/api/directions/json'

params = dict(
    origin='Chicago,IL',
    destination='Los+Angeles,CA',
    waypoints='Joplin,MO|Oklahoma+City,OK',
    sensor='false'
)

resp = requests.get(url=url, params=params)
data = resp.json() # Check the JSON Response Content documentation below

JSON Response Content: https://requests.readthedocs.io/en/master/user/quickstart/#json-response-content


The requests Python module takes care of both retrieving JSON data and decoding it, due to its builtin JSON decoder. Here is an example taken from the module's documentation:

>>> import requests
>>> r = requests.get('https://github.com/timeline.json')
>>> r.json()
[{u'repository': {u'open_issues': 0, u'url': 'https://github.com/...

So there is no use of having to use some separate module for decoding JSON.


requests has built-in .json() method

import requests
requests.get(url).json()

import urllib
import json

url = 'http://maps.googleapis.com/maps/api/directions/json?origin=Chicago,IL&destination=Los+Angeles,CA&waypoints=Joplin,MO|Oklahoma+City,OK&sensor=false'
result = json.load(urllib.urlopen(url))