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How would I go about querying for the second largest salary from all employees in my Employee table?
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We can nest the above query to find the second largest salary. select *from employee group by salary order by salary desc limit 1,1; There are other ways : SELECT name, MAX(salary) AS salary FROM employee WHERE salary IN (SELECT salary FROM employee MINUS SELECT MAX(salary) FROM employee);
Here is a way to do this task using dense_rank() function. Query : select * from( select ename, sal, dense_rank() over(order by sal desc)r from Employee) where r=&n; To find to the 2nd highest sal set n = 2 To find 3rd highest sal set n = 3 and so on.
SELECT MAX (column_name) FROM table_name WHERE column_name NOT IN (SELECT Max (column_name) FROM table_name); First we selected the max from that column in the table then we searched for the max value again in that column with excluding the max value which has already been found, so it results in the 2nd maximum value.
Try this:
SELECT max(salary) FROM emptable WHERE salary < (SELECT max(salary) FROM emptable); If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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