Thanks for a solution in C, now I would like to achieve this in C++ using std::sort and vector:
typedef struct
{
double x;
double y;
double alfa;
} pkt;
vector< pkt > wektor;
filled up using push_back(); compare function:
int porownaj(const void *p_a, const void *p_b)
{
pkt *pkt_a = (pkt *) p_a;
pkt *pkt_b = (pkt *) p_b;
if (pkt_a->alfa > pkt_b->alfa) return 1;
if (pkt_a->alfa < pkt_b->alfa) return -1;
if (pkt_a->x > pkt_b->x) return 1;
if (pkt_a->x < pkt_b->x) return -1;
return 0;
}
sort(wektor.begin(), wektor.end(), porownaj); // this makes loads of errors on compile time
What is to correct? How to use properly std::sort in that case?
std::sort
takes a different compare function from that used in qsort
. Instead of returning –1, 0 or 1, this function is expected to return a bool
value indicating whether the first element is less than the second.
You have two possibilites: implement operator <
for your objects; in that case, the default sort
invocation without a third argument will work; or you can rewrite your above function to accomplish the same thing.
Notice that you have to use strong typing in the arguments.
Additionally, it's good not to use a function here at all. Instead, use a function object. These benefit from inlining.
struct pkt_less {
bool operator ()(pkt const& a, pkt const& b) const {
if (a.alfa < b.alfa) return true;
if (a.alfa > b.alfa) return false;
if (a.x < b.x) return true;
if (a.x > b.x) return false;
return false;
}
};
// Usage:
sort(wektor.begin(), wektor.end(), pkt_less());
In C++, you can use functors like boost::bind
which do this job nicely:
#include <vector>
#include <algorithm>
struct pkt {
double x;
double y;
double alfa;
pkt(double x, double y, double alfa)
:x(x), y(y), alfa(alfa) { }
};
int main() {
std::vector<pkt> p;
p.push_back(pkt(10., 0., 20.));
p.push_back(pkt(10, 0., 30.));
p.push_back(pkt(5., 0., 40.));
std::sort(p.begin(), p.end(),
boost::bind(&pkt::alfa, _1) < boost::bind(&pkt::alfa, _2) ||
boost::bind(&pkt::alfa, _1) == boost::bind(&pkt::alfa, _2) &&
boost::bind(&pkt::x, _1) < boost::bind(&pkt::x, _2));
}
If you need to do this many times, you can also solve the problem by making a function object which accepts member pointers and does the sort. You can reuse it for any kind of object and members. First how you use it:
int main() {
/* sorting a vector of pkt */
std::vector<pkt> p;
p.push_back(pkt(10., 0., 20.));
p.push_back(pkt(5., 0., 40.));
std::sort(p.begin(), p.end(), make_cmp(&pkt::x, &pkt::y));
}
Here is the code for make_cmp. Feel free to rip it (using boost::preprocessor
):
#include <boost/preprocessor/repetition.hpp>
#include <boost/preprocessor/facilities/empty.hpp>
// tweak this to increase the maximal field count
#define CMP_MAX 10
#define TYPEDEF_print(z, n, unused) typedef M##n T::* m##n##_type;
#define MEMBER_print(z, n, unused) m##n##_type m##n;
#define CTORPARAMS_print(z, n, unused) m##n##_type m##n
#define CTORINIT_print(z, n, unused) m##n(m##n)
#define CMPIF_print(z, n, unused) \
if ((t0.*m##n) < (t1.*m##n)) return true; \
if ((t0.*m##n) > (t1.*m##n)) return false; \
#define PARAM_print(z, n, unused) M##n T::* m##n
#define CMP_functor(z, n, unused) \
template <typename T \
BOOST_PP_ENUM_TRAILING_PARAMS(n, typename M)> \
struct cmp##n { \
BOOST_PP_REPEAT(n, TYPEDEF_print, ~) \
BOOST_PP_REPEAT(n, MEMBER_print, ~) \
cmp##n(BOOST_PP_ENUM(n, CTORPARAMS_print, ~)) \
BOOST_PP_IF(n, :, BOOST_PP_EMPTY()) \
BOOST_PP_ENUM(n, CTORINIT_print, ~) { } \
\
bool operator()(T const& t0, T const& t1) const { \
BOOST_PP_REPEAT(n, CMPIF_print, ~) \
return false; \
} \
}; \
\
template<typename T \
BOOST_PP_ENUM_TRAILING_PARAMS(n, typename M)> \
cmp##n<T BOOST_PP_ENUM_TRAILING_PARAMS(n, M)> \
make_cmp(BOOST_PP_ENUM(n, PARAM_print, ~)) \
{ \
return cmp##n<T BOOST_PP_ENUM_TRAILING_PARAMS(n, M)>( \
BOOST_PP_ENUM_PARAMS(n, m)); \
}
BOOST_PP_REPEAT(CMP_MAX, CMP_functor, ~)
#undef TYPEDEF_print
#undef MEMBER_print
#undef CTORPARAMS_print
#undef CTORINIT_print
#undef CMPIF_print
#undef PARAM_print
#undef CMP_functor
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With