How to update a property of a JSON object using NewtonSoft

Question

I have a JSON string like this:

{     "code": "GENDER",     "value": { "option": "ML" } } 

I would like to update the option property to "Male" if the value is "ML" and "Female" if the value is "FM".

I have got to this point, but am unsure how to proceed:

JArray contentobject = (JArray)JsonConvert.DeserializeObject(contentJSON);   JObject voicgObj = contentobject.Children().FirstOrDefault(ce =>   ce["code"].ToString() == "GENDER") as JObject; JProperty voicgProp = voicgObj.Property("value"); 

I don't know how to get to the option which is a child of value.

Thanks in advance. Any pointers would be great.

Answer 1

You can access the object by using properties as keys:

JObject obj = JObject.Parse(json); string gender = (string)obj["value"]["option"]; 

For your example, try:

JObject obj = JObject.Parse(json); var val = obj["value"]; string option = (string)val["option"];  if (option == "ML")    val["option"] = "Male";  if (option == "FM")    val["option"] = "Female";  string result = obj.ToString(); 

Answer 2

Another way, with minimal property retrieving:

var val = voicgObj["value"] as JObject; JProperty optionProp = val.Property("option"); string option = optionProp.Value.Value<string>();  if (option == "ML")     optionProp.Value = "Male"; else if (option == "FM")     optionProp.Value = "Female";