How to unzip a file with Python 2.4?

Question

I'm having a hard time figuring out how to unzip a zip file with 2.4. extract() is not included in 2.4. I'm restricted to using 2.4.4 on my server.

Can someone please provide a simple code example?

Answer 1

You have to use namelist() and extract(). Sample considering directories

import zipfile import os.path import os zfile = zipfile.ZipFile("test.zip") for name in zfile.namelist():   (dirname, filename) = os.path.split(name)   print "Decompressing " + filename + " on " + dirname   if not os.path.exists(dirname):     os.makedirs(dirname)   zfile.extract(name, dirname) 

Answer 2

There's some problem with Vinko's answer (at least when I run it). I got:

IOError: [Errno 13] Permission denied: '01org-webapps-countingbeads-422c4e1/' 

Here's how to solve it:

# unzip a file def unzip(path):     zfile = zipfile.ZipFile(path)     for name in zfile.namelist():         (dirname, filename) = os.path.split(name)         if filename == '':             # directory             if not os.path.exists(dirname):                 os.mkdir(dirname)         else:             # file             fd = open(name, 'w')             fd.write(zfile.read(name))             fd.close()     zfile.close()