I have a tuple-
('[email protected]',)
.
I want to unpack it to get '[email protected]'.
How can I do so?
I am new to Python so please excuse.
Python uses the commas ( , ) to define a tuple, not parentheses. Unpacking tuples means assigning individual elements of a tuple to multiple variables. Use the * operator to assign remaining elements of an unpacking assignment into a list and assign it to a variable.
In python tuples can be unpacked using a function in function tuple is passed and in function, values are unpacked into a normal variable. The following code explains how to deal with an arbitrary number of arguments. “*_” is used to specify the arbitrary number of arguments in the tuple.
To index or slice a tuple you need to use the [] operator on the tuple. When indexing a tuple, if you provide a positive integer, it fetches that index from the tuple counting from the left. In case of a negative index, it fetches that index from the tuple counting from the right.
The full syntax for unpacking use the syntax for tuple literal so you can use
tu = ('[email protected]',)
(var,) = tu
The following simplified syntax is allowed
var, = tu
The prettiest way to get the first element and the last element of an iterable
object like tuple
, list
, etc. would be to use the *
feature not same as the *
operator.
my_tup = ('a', 'b', 'c',)
# Last element
*other_els, last_el = my_tup
# First element
first_el, *other_els = my_tup
# You can always do index slicing similar to lists, eg [:-1], [-1] and [0], [1:]
# Cool part is since * is not greedy (meaning zero or infinite matches work) similar to regex's *.
# This will result in no exceptions if you have only 1 element in the tuple.
my_tup = ('a',)
# This still works
# Last element
*other_els, last_el = my_tup
# First element
first_el, *other_els = my_tup
# other_els is [] here
tu = ('[email protected]',)
str = tu[0]
print(str) #will return '[email protected]'
A tuple is a sequence type, which means the elements can be accessed by their indices.
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