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How can I test if a list contains another list (ie. it's a contiguous subsequence). Say there was a function called contains:
contains([1,2], [-1, 0, 1, 2]) # Returns [2, 3] (contains returns [start, end]) contains([1,3], [-1, 0, 1, 2]) # Returns False contains([1, 2], [[1, 2], 3]) # Returns False contains([[1, 2]], [[1, 2], 3]) # Returns [0, 0] Edit:
contains([2, 1], [-1, 0, 1, 2]) # Returns False contains([-1, 1, 2], [-1, 0, 1, 2]) # Returns False contains([0, 1, 2], [-1, 0, 1, 2]) # Returns [1, 3] 
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There are 2 ways to understand check if the list contains elements of another list. First, use all() functions to check if a Python list contains all the elements of another list. And second, use any() function to check if the list contains any elements of another one.
issubset() function. The most used and recommended method to check for a sublist. This function is tailor made to perform the particular task of checking if one list is a subset of another.
USE set. issubset() TO CHECK IF A LIST IS A SUBSET OF ANOTHER LIST Use set(list) to convert the lists to sets. Call set1. issubset(set2) to return a Boolean indicating whether set1 is a subset of set2.
You can simply check to see that the set difference between query2 and query1 is the empty set: var isSubset = ! query2. Except(query1).
If all items are unique, you can use sets.
>>> items = set([-1, 0, 1, 2]) >>> set([1, 2]).issubset(items) True >>> set([1, 3]).issubset(items) False There's an all() and any() function to do this. To check if big contains ALL elements in small
result = all(elem in big for elem in small) To check if small contains ANY elements in big
result = any(elem in big for elem in small) the variable result would be boolean (TRUE/FALSE).
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