How to split a string into only two parts, by the last occurrence of the split char?

Question

For example:

"Angry Birds 2.4.1".split(" ", 2)  => ["Angry", "Birds 2.4.1"]  

How can I split the string into: ["Angry Birds", "2.4.1"]

Answer 1

String#rpartition, e.g.

irb(main):068:0> str = "Angry Birds 2.4.1" => "Angry Birds 2.4.1" irb(main):069:0> str.rpartition(' ') => ["Angry Birds", " ", "2.4.1"] 

Since the returned value is an array, using .first and .last would allow to treat the result as if it was split in two, e.g

irb(main):073:0> str.rpartition(' ').first => "Angry Birds" irb(main):074:0> str.rpartition(' ').last => "2.4.1" 

Answer 2

I hava a solution like this:

class String   def split_by_last(char=" ")     pos = self.rindex(char)     pos != nil ? [self[0...pos], self[pos+1..-1]] : [self]   end end  "Angry Birds 2.4.1".split_by_last  #=> ["Angry Birds", "2.4.1"] "test".split_by_last               #=> ["test"]