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Suppose I have the string 1:2:3:4:5 and I want to get its last field (5 in this case). How do I do that using Bash? I tried cut, but I don't know how to specify the last field with -f.
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To access the last character of a string, we can use the parameter expansion syntax ${string: -1} in the Bash shell. In bash the negative indices count from the end of a string, so -1 is the index of a last character.
In bash, a string can also be divided without using $IFS variable. The 'readarray' command with -d option is used to split the string data. The -d option is applied to define the separator character in the command like $IFS. Moreover, the bash loop is used to print the string in split form.
To access the last n characters of a string, we can use the parameter expansion syntax ${string: -n} in the Bash shell. -n is the number of characters we need to extract from the end of a string.
You can use string operators:
$ foo=1:2:3:4:5 $ echo ${foo##*:} 5 This trims everything from the front until a ':', greedily.
${foo <-- from variable foo ## <-- greedy front trim * <-- matches anything : <-- until the last ':' } If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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