how to skip a few iterations in a loop in Ruby?

Question

Suppose I have the C code below

for(i = 0; i < 10; i++){
    printf("Hello");
    if(i == 5){
        a[3] = a[2] * 2;
        if(a[3] == b)
            i = a[3];           //Skip to index = a[3]; depends on runtime value
    }
}

How to convert to Ruby? I know we can skip one iteration using next, but I have to skip a few iterations depending on conditional value and I don't know how many iterations to skip before runtime?

---

Here is the code I am actually working on (as mentioned by Coreyward):

I am looking for "straight line" in the array that the values differs less than 0.1(less than 0.1 will considered as a "straight line"). The range has to be longer than 50 to be considered as a long "line". After I find the line range [a,b], i wanna skip the iterations to upper limit b so it would not start again from a+1, and it will start to find new "straight line" from b+1

for(i=0; i<arr.Length; i++){
  if(arr[i] - arr[i + 50] < 0.1){
    m = i;                                   //m is the starting point
    for(j=i; j<arr.Length; j++){             //this loop makes sure all values differs less than 0.1
      if(arr[i] - arr[j] < 0.1){
        n = j;
      }else{
        break;
      }
    }
    if(n - m > 50){                          //Found a line with range greater than 50, and store the starting point to line array
      line[i] = m
    }
    i = n                                     //Start new search from n
  }

}

Answer 1

Your case isn't easily covered by typical ruby iterators, but ruby also has ordinary while loops which can completely cover c-for. the following is equivalent to your c for loop above.

i = 0;
while i < 10 
  puts "Hello"
  if i == 5
    a[3] = a[2] * 2
    i = a[3] if a[3] == b
  end
  # in your code above, the for increment i++ will execute after assigning new i,
  # though the comment "Skip to index = a[3]" indicates that may not be your intent
  i += 1  
end