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I understand that you can use iomanip to set a precision flags for floats (e.g. have 2.0000 as opposed to 2.00).
Is there a way possible to do this, for integers?
I would like a hex number to display as 000e8a00 rather than just e8a00 or 00000000 rather than 0.
Is this possible in C++, using the standard libraries?
430
The printf precision specifiers set the maximum number of characters (or minimum number of integer digits) to print. A printf precision specification always begins with a period (.) to separate it from any preceding width specifier.
By using the setprecision function, we can get the desired precise value of a floating-point or a double value by providing the exact number of decimal places. If an argument n is passed to the setprecision() function, then it will give n significant digits of the number without losing any information.
we now see that the format specifier "%. 2f" tells the printf method to print a floating point value (the double, x, in this case) with 2 decimal places. Similarly, had we used "%. 3f", x would have been printed rounded to 3 decimal places.
With manipulators:
std::cout << std::setfill('0') << std::setw(8) << std::hex << 0 << std::endl;
Without manipulators:
std::cout.fill('0');
std::cout.width(8);
std::cout.setf(std::ios::hex, std::ios::basefield);
std::cout << 42 << std::endl;
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