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I want to set the variable date-today to the current date, and date_dir to yesterday's date, both in the format yyyy-mm-dd.
I am doing this:
#!/bin/bash
d=`date +%y%m%d%H%M%S`
echo $d
687
To declare a date variable, use the DECLARE keyword, then type the @variable_name and variable type: date, datetime, datetime2, time, smalldatetime, datetimeoffset. In the declarative part, you can set a default value for a variable. The most commonly used default value for a date variable is the function Getdate().
#!/bin/bash now="$(date)" printf "Current date and time %s\n" "$now" now="$(date +'%d/%m/%Y')" printf "Current date in dd/mm/yyyy format %s\n" "$now" echo "Starting backup at $now, please wait..." # command to backup scripts goes here # ...
To format date in YYYY-MM-DD format, use the command date +%F or printf "%(%F)T\n" $EPOCHSECONDS . The %F option is an alias for %Y-%m-%d .
You can try:
#!/bin/bash
d=$(date +%Y-%m-%d)
echo "$d"
EDIT: Changed y to Y for 4 digit date as per QuantumFool's comment.
104
You can also use the shorter format
From the man page:
%F full date; same as %Y-%m-%d
Example:
#!/bin/bash
date_today=$(date +%F)
date_dir=$(date +%F -d yesterday)
simple:
today="$(date '+%Y-%m-%d')"
yesterday="$(date -d yesterday '+%Y-%m-%d')"
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