How can I elegantly serialize a lambda?
For example, the code below throws a NotSerializableException
. How can I fix it without creating a SerializableRunnable
"dummy" interface?
public static void main(String[] args) throws Exception {
File file = Files.createTempFile("lambda", "ser").toFile();
try (ObjectOutput oo = new ObjectOutputStream(new FileOutputStream(file))) {
Runnable r = () -> System.out.println("Can I be serialized?");
oo.writeObject(r);
}
try (ObjectInput oi = new ObjectInputStream(new FileInputStream(file))) {
Runnable r = (Runnable) oi.readObject();
r.run();
}
}
Java 8 introduces the possibility to cast an object to an intersection of types by adding multiple bounds. In the case of serialization, it is therefore possible to write:
Runnable r = (Runnable & Serializable)() -> System.out.println("Serializable!");
And the lambda automagically becomes serializable.
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With