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math. BigDecimal. add(BigDecimal val) is used to calculate the Arithmetic sum of two BigDecimals. This method is used to find arithmetic addition of large numbers of range much greater than the range of largest data type double of Java without compromising with the precision of the result.
compareTo(BigDecimal val) compares the BigDecimal Object with the specified BigDecimal value. Two BigDecimal objects that are equal in value but have a different scale (like 2.0 and 2.00) are considered equal by this method.
The BigDecimal is immutable so you need to do this:
BigDecimal result = test.add(new BigDecimal(30));
System.out.println(result);
It looks like from the Java docs here that add returns a new BigDecimal:
BigDecimal test = new BigDecimal(0);
System.out.println(test);
test = test.add(new BigDecimal(30));
System.out.println(test);
test = test.add(new BigDecimal(45));
System.out.println(test);
BigDecimal test = new BigDecimal(0);
System.out.println(test);
test = test.add(new BigDecimal(30));
System.out.println(test);
test = test.add(new BigDecimal(45));
System.out.println(test);
It's actually rather easy. Just do this:
BigDecimal test = new BigDecimal(0);
System.out.println(test);
test = test.add(new BigDecimal(30));
System.out.println(test);
test = test.add(new BigDecimal(45));
System.out.println(test);
See also: BigDecimal#add(java.math.BigDecimal)
BigInteger is immutable, you need to do this,
BigInteger sum = test.add(new BigInteger(30));
System.out.println(sum);
//you can do in this way...as BigDecimal is immutable so cant set values except in constructor
BigDecimal test = BigDecimal.ZERO;
BigDecimal result = test.add(new BigDecimal(30));
System.out.println(result);
result would be 30
BigDecimal no = new BigDecimal(10); //you can add like this also
no = no.add(new BigDecimal(10));
System.out.println(no);
20
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