Menu
I want to round the number 1732 to the nearest ten, hundred and thousand. I tried with Math round functions, but it was written only for float and double. How to do this for Integer? Is there any function in java?
262
Rounding to the Nearest IntegerIf the digit in the tenths place is less than 5, then round down, which means the units digit remains the same; if the digit in the tenths place is 5 or greater, then round up, which means you should increase the unit digit by one.
1. DecimalFormat(“0.00”) We can use DecimalFormat("0.00") to ensure the number always round to 2 decimal places. For DecimalFormat , the default rounding mode is RoundingMode.
round() is a built-in math function which returns the closest long to the argument. The result is rounded to an integer by adding 1/2, taking the floor of the result after adding 1/2, and casting the result to type long. If the argument is NaN, the result is 0.
round(1.5) will return 2 hence 2 is closer to +∞ while comparing with 1. Similarly Math. round(-1.5) will return -1 hence -1 is closer to +∞ while comparing with -2.
What rounding mechanism do you want to use? Here's a primitive approach, for positive numbers:
int roundedNumber = (number + 500) / 1000 * 1000; This will bring something like 1499 to 1000 and 1500 to 2000.
If you could have negative numbers:
int offset = (number >= 0) ? 500 : -500; int roundedNumber = (number + offset) / 1000 * 1000; 
(int)(Math.round( 1732 / 10.0) * 10) Math.round(double) takes the double and then rounds up as an nearest integer. So, 1732 will become 173.2 (input parameter) on processing by Math.round(1732 / 10.0). So the method rounds it like 173.0. Then multiplying it with 10 (Math.round( 1732 / 10.0) * 10) gives the rounded down answer, which is 173.0 will then be casted to int.
42
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With
