How to remove all subviews of a view in Swift?

Question

EDIT: (thanks Jeremiah / Rollo)

By far the best way to do this in Swift for iOS is:

view.subviews.forEach({ $0.removeFromSuperview() }) // this gets things done
view.subviews.map({ $0.removeFromSuperview() }) // this returns modified array

^^ These features are fun!

let funTimes = ["Awesome","Crazy","WTF"]
extension String { 
    func readIt() {
        print(self)
    }
}

funTimes.forEach({ $0.readIt() })

//// END EDIT

Just do this:

for view in self.view.subviews {
    view.removeFromSuperview()
}

Or if you are looking for a specific class

for view:CustomViewClass! in self.view.subviews {
        if view.isKindOfClass(CustomViewClass) {
            view.doClassThing()
        }
    }

For iOS/Swift, to get rid of all subviews I use:

for v in view.subviews{
   v.removeFromSuperview()
}

to get rid of all subviews of a particular class (like UILabel) I use:

for v in view.subviews{
   if v is UILabel{
      v.removeFromSuperview()
   }
}

The code can be written simpler as following.

view.subviews.forEach { $0.removeFromSuperview() }

This should be the simplest solution.

let container_view: NSView = ...
container_view.subviews = []

(see Remove all subviews? for other methods)

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Note this is a MacOS question and this answer works only for MacOS. It does not work on iOS.