How to read mutliline input from stdin into variable and how to print one out in shell(sh,bash)?

Question

This is working for me:

myvar=`cat`

echo "$myvar"

The quotes around $myvar are important.

In Bash, there's an alternative way; man bash mentions:

The command substitution $(cat file) can be replaced by the equivalent but faster $(< file).

$ myVar=$(</dev/stdin)
hello
this is test
$ echo "$myVar"
hello
this is test

tee does the job

#!/bin/bash
myVar=$(tee)

[updated]

This assignment will hang indefinitely if there is nothing in the pipe...

var="$(< /dev/stdin)"

We can prevent this though by doing a timeout read for the first character. If it times out, the return code will be greater than 128 and we'll know the STDIN pipe (a.k.a /dev/stdin) is empty.

Otherwise, we get the rest of STDIN by...

• setting IFS to NULL for just the read command
• turning off escapes with -r
• eliminating read's delimiter with -d ''.
• and finally, appending that to the character we got initially

Thus...

__=""
_stdin=""

read -N1 -t1 __  && {
  (( $? <= 128 ))  && {
    IFS= read -rd '' _stdin
    _stdin="$__$_stdin"
  }
}

This technique avoids using var="$(command ...)" Command Substitution which, by design, will always strip off any trailing newlines.

If Command Substitution is preferred, to preserve trailing newlines we can append one or more delimiter characters to the output inside the $() and then strip them off outside.

For example ( note $(parens) in first command and ${braces} in second )...

_stdin="$(awk '{print}; END {print "|||"}' /dev/stdin)"
_stdin="${_stdin%|||}"