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How to properly triangulate GSM cell towers to get a location?

First of all, I am trying to do all this disaster in c# (.net 4) so if you come up with some code to help me that would be appreciated but really anything would help at this point.

I have a situation where I have a device that can only get GSM Cell information (incidentally via the AT+KCELL command) so I have a collection of values about cell towers (each has LAC, MCC, MNC, Cell ID, Signal Strength and the first Timing Advance). I think, therefore, I am in a good place to be able to come up with some sort of longitude and latitude coordinate (albeit inaccurate, but, well meh). This is where I am reaching out for help because now my little brain is confused...

I can see various services that provide cell code resolution (Google, Open Cell ID, etc) and they take LAC,MCC etc as arguments and return a coordinate. I figure that what they return would, therefore, be the coordinate of the given tower I pass in. So in my case I could send off all the LACs etc that I have and get back a collection of longitude and latitudes. Brilliant, but that is not where my device is. Now I think I need to do some kind of triangulation and this is where my lack of knowledge is hurting me.

So am I right so far? Assuming I am, how do I perform this calculation (is there something out there that will tell me what to do with all these numbers or, even better, some open source library I can reference and feed all this stuff into to get something sensible)?

I'm assuming that I would need to use the timing advance to work out some approximate distance from a cell tower (maybe using the signal strength somehow) but what do I have to do? As you can tell - I am way out of my depth here!

For example, this is something I might get back from the aforementioned AT command:

5,74,33,32f210,157e,8101,50,0,79,3,32f210,157e,80f7,37,64,5,32f210,157e,810b,37,55,32,32f210,157e,9d3,27,41,33,32f210,157e,edf8,15 

breaking it up and parsing it I would get (I hope I parse this right - there is a chance there is a bug in my parsing routine of course but it looks reasonable):

Number of cells: 5 

Cell 1

LAC: 5502 MNC: 1 MCC: 232 Cell ID: 33025 Signal: 80 ARFCN: 74 BSIC: 33 Timing advance: 0 Longitude: 14.2565389 Latitude: 48.2248439 

Cell 2

LAC: 5502 MNC: 1 MCC: 232 Cell ID: 33015 Signal: 55 ARFCN: 79 BSIC: 3 Longitude: 14.2637736 Latitude: 48.2331576 

Cell 3

LAC: 5502 MNC: 1 MCC: 232 Cell ID: 33035 Signal: 55 ARFCN: 64 BSIC: 5 Longitude: 14.2488966 Latitude: 48.232513 

Cell 4

LAC: 5502 MNC: 1 MCC: 232 Cell ID: 2515 Signal: 39 ARFCN: 55 BSIC: 32 Longitude: 14.2488163 Latitude: 48.2277972 

Cell 5

LAC: 5502 MNC: 1 MCC: 232 Cell ID: 60920 Signal: 21 ARFCN: 41 BSIC: 33 Longitude: 14.2647612 Latitude: 48.2299558 

So with all that information how do I find, in the most accurate way, where I actually am?

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kmp Avatar asked Apr 26 '12 08:04

kmp


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1 Answers

I can help you with a bit of the theory.

Triangulation is basically finding the intersection point of 3 circles.

Each mobile tower is the center of a circle. The size of the circle is relative to the signal strength of that tower.

The place where the 3 circles overlap is where the user is.

You can do some very basic triangulation as follows:

 3 Towers at   tx1,ty1   tx2,ty2   tx3,ty3  With signal strengths s1, s2, s3  We calculate the weight of each signal. Essentially a number from 0 to 1 for each tower where the sum of the weights adds up to 1.  Weighted signal w1, w2, w3 where:  w1 = s1/(s1+s2+s3)  w2 = s2/(s1+s2+s3)  w3 = s3/(s1+s2+s3)   User will be at x: (w1 * tx1 + w2 * tx2+ w3 * tx3) y: (w1 * ty1 + w2 * ty2+ w3 * ty3)  

Here is a working example using the values from your question:

  s1 = 80 s2 = 55 s3 = 55 s4 = 55 s5 = 21  w1 = 80 / ( 80 + 55 + 55 + 55 + 21 )  w2 = 55 / ( 80 + 55 + 55 + 55 + 21 )  w3 = 55 / ( 80 + 55 + 55 + 55 + 21 )  w4 = 55 / ( 80 + 55 + 55 + 55 + 21 )  w5 = 21 / ( 80 + 55 + 55 + 55 + 21 )   w1 = 0.3007519 w2 = 0.2067669 w3 = 0.2067669 w4 = 0.2067669 w5 = 0.0789474  1. Longitude: 14.2565389 1. Latitude: 48.2248439  2. Longitude: 14.2637736 2. Latitude: 48.2331576  3. Longitude: 14.2488966 3. Latitude: 48.232513  4. Longitude: 14.2488163 4. Latitude: 48.2277972   5. Longitude: 14.2647612 5. Latitude: 48.2299558   Location Longitude =   14.2565389 * 0.3007519 +   14.2637736 * 0.2067669 +   14.2488966 * 0.2067669 +  14.2488163 * 0.2067669 +  14.2647612 * 0.0789474  Location Latitude: =   48.2248439 * 0.3007519 +   48.2331576 * 0.2067669 +   48.232513 * 0.2067669 +  48.2277972 * 0.2067669 +  48.2299558 * 0.0789474  Result Longitude: 14.255507 Result Latitude: 48.2291628  
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Jared Kells Avatar answered Sep 26 '22 23:09

Jared Kells