put("email", "[email protected]"); RestTemplate restTemplate = new RestTemplate(); ResponseEntity<String> response = restTemplate. postForEntity( url, params, String. class );
Posting JSON With postForObject. RestTemplate's postForObject method creates a new resource by posting an object to the given URI template. It returns the result as automatically converted to the type specified in the responseType parameter.
The POST method should be sent along the HTTP request object. And the request may contain either of HTTP header or HTTP body or both.
Hence let's create an HTTP entity and send the headers and parameter in body.
HttpHeaders headers = new HttpHeaders();
headers.setContentType(MediaType.APPLICATION_FORM_URLENCODED);
MultiValueMap<String, String> map= new LinkedMultiValueMap<String, String>();
map.add("email", "[email protected]");
HttpEntity<MultiValueMap<String, String>> request = new HttpEntity<MultiValueMap<String, String>>(map, headers);
ResponseEntity<String> response = restTemplate.postForEntity( url, request , String.class );
http://docs.spring.io/spring/docs/current/javadoc-api/org/springframework/web/client/RestTemplate.html#postForObject-java.lang.String-java.lang.Object-java.lang.Class-java.lang.Object...-
How to POST mixed data: File, String[], String in one request.
You can use only what you need.
private String doPOST(File file, String[] array, String name) {
RestTemplate restTemplate = new RestTemplate(true);
//add file
LinkedMultiValueMap<String, Object> params = new LinkedMultiValueMap<>();
params.add("file", new FileSystemResource(file));
//add array
UriComponentsBuilder builder = UriComponentsBuilder.fromHttpUrl("https://my_url");
for (String item : array) {
builder.queryParam("array", item);
}
//add some String
builder.queryParam("name", name);
//another staff
String result = "";
HttpHeaders headers = new HttpHeaders();
headers.setContentType(MediaType.MULTIPART_FORM_DATA);
HttpEntity<LinkedMultiValueMap<String, Object>> requestEntity =
new HttpEntity<>(params, headers);
ResponseEntity<String> responseEntity = restTemplate.exchange(
builder.build().encode().toUri(),
HttpMethod.POST,
requestEntity,
String.class);
HttpStatus statusCode = responseEntity.getStatusCode();
if (statusCode == HttpStatus.ACCEPTED) {
result = responseEntity.getBody();
}
return result;
}
The POST request will have File in its Body and next structure:
POST https://my_url?array=your_value1&array=your_value2&name=bob
here is the full program to make a POST rest call using spring's RestTemplate.
import java.util.HashMap;
import java.util.Map;
import org.springframework.http.HttpEntity;
import org.springframework.http.ResponseEntity;
import org.springframework.util.LinkedMultiValueMap;
import org.springframework.util.MultiValueMap;
import org.springframework.web.client.RestTemplate;
import com.ituple.common.dto.ServiceResponse;
public class PostRequestMain {
public static void main(String[] args) {
// TODO Auto-generated method stub
MultiValueMap<String, String> headers = new LinkedMultiValueMap<String, String>();
Map map = new HashMap<String, String>();
map.put("Content-Type", "application/json");
headers.setAll(map);
Map req_payload = new HashMap();
req_payload.put("name", "piyush");
HttpEntity<?> request = new HttpEntity<>(req_payload, headers);
String url = "http://localhost:8080/xxx/xxx/";
ResponseEntity<?> response = new RestTemplate().postForEntity(url, request, String.class);
ServiceResponse entityResponse = (ServiceResponse) response.getBody();
System.out.println(entityResponse.getData());
}
}
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