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Java switch statement: Constant expression required, but it IS constant

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How do you solve a constant error required in java?

The fix is simple; change the Foo.BA* variable declarations to have initializers that are compile-time constant expressions. In other examples (where the initializers are already compile-time constant expressions), declaring the variable as final may be what is needed.

What does constant expression required mean in java?

A constant expression is an expression that yields a primitive type or a String, and whose value can be evaluated at compile time to a literal. The expression must evaluate without throwing an exception, and it must be composed of only the following: Primitive and String literals.

How do you create a constant expression in java?

To make any variable a constant, we must use 'static' and 'final' modifiers in the following manner: Syntax to assign a constant value in java: static final datatype identifier_name = constant; The static modifier causes the variable to be available without an instance of it's defining class being loaded.

What is the meaning of constant expression required error?

A constant must be initialized. This error has the following causes and solutions: You tried to initialize a constant with a variable, an instance of a user-defined type, an object, or the return value of a function call.


I understand that the compiler needs the expression to be known at compile time to compile a switch, but why isn't Foo.BA_ constant?

While they are constant from the perspective of any code that executes after the fields have been initialized, they are not a compile time constant in the sense required by the JLS; see §15.28 Constant Expressions for the specification of a constant expression1. This refers to §4.12.4 Final Variables which defines a "constant variable" as follows:

We call a variable, of primitive type or type String, that is final and initialized with a compile-time constant expression (§15.28) a constant variable. Whether a variable is a constant variable or not may have implications with respect to class initialization (§12.4.1), binary compatibility (§13.1, §13.4.9) and definite assignment (§16).

In your example, the Foo.BA* variables do not have initializers, and hence do not qualify as "constant variables". The fix is simple; change the Foo.BA* variable declarations to have initializers that are compile-time constant expressions.

In other examples (where the initializers are already compile-time constant expressions), declaring the variable as final may be what is needed.

You could change your code to use an enum rather than int constants, but that brings another couple of different restrictions:

  • You must include a default case, even if you have case for every known value of the enum; see Why is default required for a switch on an enum?
  • The case labels must all be explicit enum values, not expressions that evaluate to enum values.

1 - The constant expression restrictions can be summarized as follows. Constant expressions a) can use primitive types and String only, b) allow primaries that are literals (apart from null) and constant variables only, c) allow constant expressions possibly parenthesised as subexpressions, d) allow operators except for assignment operators, ++, -- or instanceof, and e) allow type casts to primitive types or String only.

Note that this doesn't include any form of method or lambda calls, new, .class. .length or array subscripting. Furthermore, any use of array values, enum values, values of primitive wrapper types, boxing and unboxing are all excluded because of a).


You get Constant expression required because you left the values off your constants. Try:

public abstract class Foo {
    ...
    public static final int BAR=0;
    public static final int BAZ=1;
    public static final int BAM=2;
    ...
}

I got this error on Android, and my solution was just to use:

public static final int TAKE_PICTURE = 1;

instead of

public static int TAKE_PICTURE = 1;

Because those are not compile time constants. Consider the following valid code:

public static final int BAR = new Random().nextInt();

You can only know the value of BAR in runtime.


You can use an enum like in this example:

public class MainClass {
enum Choice { Choice1, Choice2, Choice3 }
public static void main(String[] args) {
Choice ch = Choice.Choice1;

switch(ch) {
  case Choice1:
    System.out.println("Choice1 selected");
    break;
 case Choice2:
   System.out.println("Choice2 selected");
   break;
 case Choice3:
   System.out.println("Choice3 selected");
   break;
    }
  }
}

Source: Switch statement with enum


I recommend using the following way:

public enum Animal {
    DOG("dog"), TIGER("tiger"), LION("lion");
    private final String name;

    @Override
    public String toString() {
        return this.name;
    }
}


public class DemoSwitchUsage {

     private String getAnimal(String name) {
         Animal animalName = Animal.valueOf(name);
         switch(animalName) {
         case DOG:
             // write the code required.
             break;
         case LION:
             // Write the code required.
             break;
         default:
             break;
         }
     }
}