I have a pandas dataframe and would like to plot values from one column versus the values from another column. Fortunately, there is plot
method associated with the data-frames that seems to do what I need:
df.plot(x='col_name_1', y='col_name_2')
Unfortunately, it looks like among the plot styles (listed here after the kind
parameter) there are not points. I can use lines or bars or even density but not points. Is there a work around that can help to solve this problem.
To plot a specific column, use the selection method of the subset data tutorial in combination with the plot() method. Hence, the plot() method works on both Series and DataFrame .
You can specify the style
of the plotted line when calling df.plot
:
df.plot(x='col_name_1', y='col_name_2', style='o')
The style
argument can also be a dict
or list
, e.g.:
import numpy as np import pandas as pd d = {'one' : np.random.rand(10), 'two' : np.random.rand(10)} df = pd.DataFrame(d) df.plot(style=['o','rx'])
All the accepted style formats are listed in the documentation of matplotlib.pyplot.plot
.
For this (and most plotting) I would not rely on the Pandas wrappers to matplotlib. Instead, just use matplotlib directly:
import matplotlib.pyplot as plt plt.scatter(df['col_name_1'], df['col_name_2']) plt.show() # Depending on whether you use IPython or interactive mode, etc.
and remember that you can access a NumPy array of the column's values with df.col_name_1.values
for example.
I ran into trouble using this with Pandas default plotting in the case of a column of Timestamp values with millisecond precision. In trying to convert the objects to datetime64
type, I also discovered a nasty issue: < Pandas gives incorrect result when asking if Timestamp column values have attr astype >.
Pandas
uses matplotlib
as a library for basic plots. The easiest way in your case will using the following:
import pandas as pd
import numpy as np
#creating sample data
sample_data={'col_name_1':np.random.rand(20),
'col_name_2': np.random.rand(20)}
df= pd.DataFrame(sample_data)
df.plot(x='col_name_1', y='col_name_2', style='o')
However, I would recommend to use seaborn
as an alternative solution if you want have more customized plots while not going into the basic level of matplotlib.
In this case you the solution will be following:
import pandas as pd
import seaborn as sns
import numpy as np
#creating sample data
sample_data={'col_name_1':np.random.rand(20),
'col_name_2': np.random.rand(20)}
df= pd.DataFrame(sample_data)
sns.scatterplot(x="col_name_1", y="col_name_2", data=df)
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