Capture stdout from a script?

Question

suppose there is a script doing something like this:

# module writer.py
import sys

def write():
    sys.stdout.write("foobar")

Now suppose I want to capture the output of the write function and store it in a variable for further processing. The naive solution was:

# module mymodule.py
from writer import write

out = write()
print out.upper()

But this doesn't work. I come up with another solution and it works, but please, let me know if there is a better way to solve the problem. Thanks

import sys
from cStringIO import StringIO

# setup the environment
backup = sys.stdout

# ####
sys.stdout = StringIO()     # capture output
write()
out = sys.stdout.getvalue() # release output
# ####

sys.stdout.close()  # close the stream 
sys.stdout = backup # restore original stdout

print out.upper()   # post processing

Answer 1

For future visitors: Python 3.4 contextlib provides for this directly (see Python contextlib help) via the redirect_stdout context manager:

from contextlib import redirect_stdout
import io

f = io.StringIO()
with redirect_stdout(f):
    help(pow)
s = f.getvalue()

Answer 2

Setting stdout is a reasonable way to do it. Another is to run it as another process:

import subprocess

proc = subprocess.Popen(["python", "-c", "import writer; writer.write()"], stdout=subprocess.PIPE)
out = proc.communicate()[0]
print out.upper()

Answer 3

Here is a context manager version of your code. It yields a list of two values; the first is stdout, the second is stderr.

import contextlib
@contextlib.contextmanager
def capture():
    import sys
    from cStringIO import StringIO
    oldout,olderr = sys.stdout, sys.stderr
    try:
        out=[StringIO(), StringIO()]
        sys.stdout,sys.stderr = out
        yield out
    finally:
        sys.stdout,sys.stderr = oldout, olderr
        out[0] = out[0].getvalue()
        out[1] = out[1].getvalue()

with capture() as out:
    print 'hi'

Answer 4

Starting with Python 3 you can also use sys.stdout.buffer.write() to write (already) encoded byte strings to stdout (see stdout in Python 3). When you do that, the simple StringIO approach doesn't work because neither sys.stdout.encoding nor sys.stdout.buffer would be available.

Starting with Python 2.6 you can use the TextIOBase API, which includes the missing attributes:

import sys
from io import TextIOWrapper, BytesIO

# setup the environment
old_stdout = sys.stdout
sys.stdout = TextIOWrapper(BytesIO(), sys.stdout.encoding)

# do some writing (indirectly)
write("blub")

# get output
sys.stdout.seek(0)      # jump to the start
out = sys.stdout.read() # read output

# restore stdout
sys.stdout.close()
sys.stdout = old_stdout

# do stuff with the output
print(out.upper())

This solution works for Python 2 >= 2.6 and Python 3. Please note that our sys.stdout.write() only accepts unicode strings and sys.stdout.buffer.write() only accepts byte strings. This might not be the case for old code, but is often the case for code that is built to run on Python 2 and 3 without changes.

If you need to support code that sends byte strings to stdout directly without using stdout.buffer, you can use this variation:

class StdoutBuffer(TextIOWrapper):
    def write(self, string):
        try:
            return super(StdoutBuffer, self).write(string)
        except TypeError:
            # redirect encoded byte strings directly to buffer
            return super(StdoutBuffer, self).buffer.write(string)

You don't have to set the encoding of the buffer the sys.stdout.encoding, but this helps when using this method for testing/comparing script output.