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I have a wallop of a string with many lines. How do I read the lines one by one with a for clause? Here is what I am trying to do and I get an error on the textData var referenced in the for line in textData line.
for line in textData print line lineResult = libLAPFF.parseLine(line) The textData variable does exist, I print it before going down, but I think that the pre-compiler is kicking up the error.
643
str. splitlines() is the way to go.
The new line character in Python is \n . It is used to indicate the end of a line of text. You can print strings without adding a new line with end = <character> , which <character> is the character that will be used to separate the lines.
In Python, the new line character “\n” is used to create a new line. When inserted in a string all the characters after the character are added to a new line. Essentially the occurrence of the “\n” indicates that the line ends here and the remaining characters would be displayed in a new line.
For each line in lines , we call str. strip() to remove any whitespace and non-printing characters from the ENDS of each line. Finally, we call '\t'. join() on the resulting list to insert tabs.
What about using .splitlines()?
for line in textData.splitlines(): print(line) lineResult = libLAPFF.parseLine(line) by splitting with newlines.
for line in wallop_of_a_string_with_many_lines.split('\n'): #do_something.. if you iterate over a string, you are iterating char by char in that string, not by line.
>>>string = 'abc' >>>for line in string: print line a b c If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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