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How to pass parameters to another process in c#

I just created an application that launches processes with the following code

string [] args = {"a", "b"};
             Process.Start ("C: \ \ demo.exe" String.Join ("", args));

I would like to be able to pass the parameters from this application to the process I've launched.

where I have to enter the parameters in the project of the process that I've launched? I tried to put them in

static void Main (string [] args) {...

but they are not available in other forms. thanks for the help

like image 755
Ldg Avatar asked Apr 17 '13 09:04

Ldg


2 Answers

Process p= new Process();
p.StartInfo.FileName = "demo.exe";
p.StartInfo.Arguments = "a b";
p.Start();

or

Process.Start("demo.exe", "a b");

in demo.exe

static void Main (string [] args)
{
  Console.WriteLine(args[0]);
  Console.WriteLine(args[1]);
}

You asked how to save these params. You can create new class with static properties and save these params there.

class ParamHolder
{
  public static string[] Params { get; set;}
}

and in main

static void Main (string [] args)
{
  ParamHolder.Params = args;
}

to get params in any place of your program use:

Console.WriteLine(ConsoleParamHolder.Params[0]);
Console.WriteLine(ConsoleParamHolder.Params[1]);

etc.

like image 113
Robert Avatar answered Sep 21 '22 10:09

Robert


Main Application code:

var process = new Process();
process.StartInfo.FileName = "demo.exe" // Path to your demo application.
process.StartInfo.Arguments = "a b c"   // Your arguments
process.Start();

In your demo application (I am assuming that this is console application)

static void Main (string [] args)
{
    var agrumentOne = args[0];
    var agrumentTwo = args[1];
    var agrumentThree = args[3];
}

Here argumentOne, argumentTwo, argumentThree will contain "a", "b" and "c".

like image 27
fhnaseer Avatar answered Sep 20 '22 10:09

fhnaseer