How to pass filename through variable to be read it by awk

Question

Good day,

I was wondering how to pass the filename to awk as variable, in order to awk read it.

So far I have done:

echo    file1   >  Aenumerar
echo    file2   >> Aenumerar
echo    file3   >> Aenumerar

AE=`grep -c '' Aenumerar`
r=1
while [ $r -le $AE ]; do
    lista=`awk "NR==$r {print $0}" Aenumerar`
    AEList=`grep -c '' $lista`
    s=1
    while [ $s -le $AEList ]; do
        word=`awk -v var=$s 'NR==var {print $1}' $lista`
        echo $word
    let "s = s + 1"
    done
let "r = r + 1"
done

Thanks so much in advance for any clue or other simple way to do it with bash command line

Answer 1

Instead of:

awk "NR==$r {print $0}" Aenumerar

You need to use:

awk -v r="$r" 'NR==r' Aenumerar