How to know if a number is odd or even in Swift?

Question

I have an array of numbers typed Int.

I want to loop through this array and determine if each number is odd or even.

How can I determine if a number is odd or even in Swift?

Answer 1

var myArray = [23, 54, 51, 98, 54, 23, 32]; for myInt: Int in myArray{   if myInt % 2 == 0 {     println("\(myInt) is even number")   } else {     println("\(myInt) is odd number")   } } 

Answer 2

Use the % Remainder Operator (aka the Modulo Operator) to check if a number is even:

if yourNumber % 2 == 0 {   // Even Number } else {   // Odd Number } 

or, use remainder(dividingBy:) to make the same check:

if yourNumber.remainder(dividingBy: 2) == 0 {                   // Even Number  } else {   // Odd Number }