How to include the `-e` argument in the `$@` bash variable?

Question

I'm creating a bash script which will wrap a docker run command, passing in all arguments. The docker cmd being run has a -e parameter like so:

docker run --rm -it --name some_name -v $(pwd):/some_dir some_image some_command -e -r -t

However, the bash script for some reason is not passing in the -e parameter.

For example I have the following test.sh script.

#!/bin/bash
echo "Echoing the command arguments."
echo $@

The -e parameter is not passed through to $@ when in the first position.

$ ./test.sh -e -r -t
Echoing the command arguments.
-r -t

$ ./test.sh -r -e -t
Echoing the command arguments.
-r -e -t

Ultimately I would like to be able to call the docker command as follows, simply passing in all given parameters from the bash script to the docker command.

docker run --rm -it --name some_name -v $(pwd):/some_dir some_image some_command $@

This may be confusing to users if they are expecting the -e parameter to be passed in and the associate activity does not happen.

Is there a way to allow the -e parameter to pass through?

Answer 1

Change your test to:

#!/bin/bash
echo "Echoing the command arguments:"
printf ' - %q\n' "$@"

...and you'll see -e present.

A POSIX-conforming implementation of echo will print -e on output when given that string as its first argument. bash's implementation does not comply unless both set -o posix and shopt -s xpg_echo runtime options are set.