I have a vector x
of the form:
x=c(601, 602, 603, 604, 605, 606, 607, 608, 609, 610, 611, 612, 613, 614,
615, 616, 617, 618, 619, 620, 621, 622, 623, 624, 625, 626, 627, 628, 629, 630,
631, 632, 633, 634, 635, 636, 637, 638, 639, 640, 641, 642, 643, 644, 645, 646,
647, 648, 649, 650)
If length (x) == 50
: I would like to test (TRUE or FALSE) if x is exactly equal to one of the intervals 1:50 or 51:100 or 101:150 or 151:200 .... or 951:1000.
Or if length (x)> 50
, I would like to test (TRUE or FALSE) if x is exactly equal to the union of intervals composed by ((1:50 U 51: 100) or (1:50 U 101: 150) or (51 : 100 U 151: 200) ....).
My attempt:
all(
x == c(1:50) |
x == c(51:100) |
x == c(101:150) |
x == c(151:200) |
x == c(201:250) |
x == c(251:300) |
x == c(301:350) |
x == c(351:400) |
x == c(401:450) |
x == c(451:500) |
x == c(501:550) |
x == c(551:600) |
x == c(601:650) |
x == c(651:700) |
x == c(701:750) |
x == c(751:800) |
x == c(801:850) |
x == c(851:900) |
x == c(901:950) |
x == c(951:1000)
)
I would like to optimize this code.
PS: I'm not trying to have a frequency table of the x
elements and intervals like this question. I want to know if x
corresponds exactly to one or the union of those intervals.
You can use cut
, i.e.
unique(cut(x, breaks = seq(0, 1000, by = 50)))
#[1] (600,650]
If you want a boolean If x
is included in one those intervals, then you can do,
unique(cut(x, breaks = seq(0, 1000, by = 50))) != ''
#[1] TRUE
#or If you only want to be in 1 group, then as suggested by Ronak,
length(unique(cut(x, breaks = seq(0, 1000, by = 50)))) == 1
#[1] TRUE
a data.table
solution:
test <- function(u){
ifelse(all(as.data.table(u)[,
.N,
by = cut(u,
breaks = seq(0, 1000, 50))][, unique(N)] == 50),
TRUE,
FALSE)
}
x <- 1:50 # TRUE
y <- 2:51 # FALSE
z <- 1:100 # TRUE
w <- 2:101 # FALSE
test(x)
> TRUE
test(y)
> FALSE
test(z)
> TRUE
test(w)
> FALSE
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