I am new to shell scripting and can't figure this out. If you are unfamiliar, the command git branch returns something like
* develop master
, where the asterisk marks the currently checked out branch. When I run the following in the terminal:
git branch | grep "*"
I get:
* develop
as expected.
However, when I run
test=$(git branch | grep "*")
or
test=`git branch | grep "*"`
And then
echo $test
, the result is just a list of files in the directory. How do we make the value of test="* develop"?
Then the next step (once we get "* develop" into a variable called test), is to get the substring. Would that just be the following?
currentBranch=${test:2}
I was playing around with that substring function and I got "bad substitution" errors a lot and don't know why.
$_ (dollar underscore) is another special bash parameter and used to reference the absolute file name of the shell or bash script which is being executed as specified in the argument list. This bash parameter is also used to hold the name of mail file while checking emails.
bash [filename] runs the commands saved in a file. $@ refers to all of a shell script's command-line arguments. $1 , $2 , etc., refer to the first command-line argument, the second command-line argument, etc. Place variables in quotes if the values might have spaces in them.
The git branch command lets you rename a branch. To rename a branch, run git branch -m <old> <new>. “old” is the name of the branch you want to rename and “new” is the new name for the branch.
The * is expanded, what you can do is use sed instead of grep and get the name of the branch immediately:
branch=$(git branch | sed -n -e 's/^\* \(.*\)/\1/p')
And a version using git symbolic-ref, as suggested by Noufal Ibrahim
branch=$(git symbolic-ref HEAD | sed -e 's,.*/\(.*\),\1,')
To elaborate on the expansion, (as marco already did,) the expansion happens in the echo, when you do echo $test
with $test
containing * master
then the *
is expanded according to the normal expansion rules. To suppress this one would have to quote the variable, as shown by marco: echo "$test"
. Alternatively, if you get rid of the asterisk before you echo it, all will be fine, e.g. echo ${test:2}
will just echo master
. Alternatively you could assign it anew as you already proposed:
branch=${test:2} echo $branch
This will echo master
, like you wanted.
Expanding on Noufal Ibrahim's answer, use the --short
flag with git-symbolic-ref
, no need to fuss with sed
.
I've been using something like this in hooks and it works well:
#!/bin/bash branch=$(git symbolic-ref --short HEAD) echo echo "**** Running post-commit hook from branch $branch" echo
That outputs "**** Running post-commit hook from branch master"
Note that git-symbolic-ref
only works if you're in a repository. Luckily .git/HEAD
, as a leftover from Git's early days, contains the same symbolic ref. If you want to get the active branch of several git repositories, without traversing directories, you could use a bash one-liner like this:
for repo in */.git; do branch=$(cat $repo/HEAD); echo ${repo%/.git} : ${branch##*/}; done
Which outputs something like:
repo1 : master repo2 : dev repo3 : issue12
If you want to go further, the full ref contained in .git/HEAD
is also a relative path to a file containing the SHA-1 hash of the branch's last commit.
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With