How can I find all zero-byte files in a directory and its subdirectories?
I have done this:
#!/bin/bash lns=`vdir -R *.* $dir| awk '{print $8"\t"$5}'` temp="" for file in $lns; do if test $file = "0"; then printf $temp"\t"$file"\n" fi temp=$file done
But, I only get results in the current directory, not subdirs, and if any file name contains a space then I get only first word followed by tab
If you just want to get a list of zero byte sized files, remove the -exec and -delete options. This will cause find to print out the list of empty files.
The -s option to the test builtin check to see if FILE exists and has a size greater than zero. It returns true and false values to indicate that file is empty or has some data.
Delete Empty Files in a Directory -type f -empty -print, will find all the empty files in the given directory recursively.
To print the names of all files in and below $dir of size 0:
find "$dir" -size 0
Note that not all implementations of find
will produce output by default, so you may need to do:
find "$dir" -size 0 -print
Two comments on the final loop in the question:
Rather than iterating over every other word in a string and seeing if the alternate values are zero, you can partially eliminate the issue you're having with whitespace by iterating over lines. eg:
printf '1 f1\n0 f 2\n10 f3\n' | while read size path; do test "$size" -eq 0 && echo "$path"; done
Note that this will fail in your case if any of the paths output by ls contain newlines, and this reinforces 2 points: don't parse ls
, and have a sane naming policy that doesn't allow whitespace in paths.
Secondly, to output the data from the loop, there is no need to store the output in a variable just to echo
it. If you simply let the loop write its output to stdout, you accomplish the same thing but avoid storing it.
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