using below for loop to see all help options for dictionaries
for me in dir(dict):
if not me.startswith("__"):
help(dict.me)
error is AttributeError: type object 'dict' has no attribute me
Once resolve it i can see all data types help options
Python is a dynamically-typed language, which means that we don't have to specify data types when we create variables and functions. While this reduces the amount of code we need to write, the workload that we save is in turn added to the next developer that needs to understand and debug the existing function!
Python is an object-orientated language, and as such it uses classes to define data types, including its primitive types.
pivoting from the only answer and your question:
for me in dir(dict):
if not me.startswith('__'):
help(getattr(dict, me))
for me in dir(dict):
if not me.startswith('__'):
help(me)
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