How to get default blue colour of matplotlib.pyplot.scatter?

Question

How do I get the shade of blue that is used as default in matplotlib.pyplot.scatter? When giving the keyword argument c='b', it gives a darker shade of blue. In this documentation of matplotlib.pyplot.scatter, it says the default is supposed to be 'b', yet it looks different.

See example below:

import matplotlib.pyplot as plt fig, ax = plt.subplots() ax.scatter(-1, 0) ax.text(-1, 0, 'Default blue') ax.scatter(1, 0, c='b') ax.text(1, 0, 'Darker blue') ax.set_xlim(-2, 2) 

I'm using Python 3.5 with Matplotlib 2.0.0. The reason why I'm asking this, is because I would like to use the same blue colour when plotting some of the points one by one with plt.plot().

Answer 1

The default colour cycle was changed in matplotlib version 2 as shown in the docs.

Therefore, to plot the "new" default blue you can do 2 things:

fig, ax = plt.subplots()  ax.scatter(-1, 1) ax.text(-0.9, 1, 'Default blue')  ax.scatter(1, 1, c='#1f77b4') ax.text(1.1, 1, 'Using hex value')  ax.scatter(0, 0.5, c='C0') ax.text(0.1, 0.5, 'Using "C0" notation')  ax.set_xlim(-2, 3) ax.set_ylim(-1,2) plt.show() 

Which gives:

Alternatively you can change the colour cycle back to what it was:

import matplotlib as mpl from cycler import cycler  mpl.rcParams['axes.prop_cycle'] = cycler(color='bgrcmyk')