Try as.numeric(mydata$datefield[120])
:
gg + geom_vline(xintercept=as.numeric(mydata$datefield[120]), linetype=4)
A simple test example:
library("ggplot2")
tmp <- data.frame(x=rep(seq(as.Date(0, origin="1970-01-01"),
length=36, by="1 month"), 2),
y=rnorm(72),
category=gl(2,36))
p <- ggplot(tmp, aes(x, y, colour=category)) +
geom_line() +
geom_vline(xintercept=as.numeric(tmp$x[c(13, 24)]),
linetype=4, colour="black")
print(p)
You could also do geom_vline(xintercept = as.numeric(as.Date("2015-01-01")), linetype=4)
if you want the line to stay in place whether or not your date is in the 120th row.
Depending on how you pass your "Dates" column to aes
, either as.numeric
or as.POSIXct
works:
library(ggplot2)
using aes(as.Date(Dates),...)
ggplot(df, aes(as.Date(Dates), value)) +
geom_line() +
geom_vline(xintercept = as.numeric(as.Date("2020-11-20")),
color = "red",
lwd = 2)
using aes(Dates, ...)
ggplot(df, aes(Dates, value)) +
geom_line() +
geom_vline(xintercept = as.POSIXct(as.Date("2020-11-20")),
color = "red",
lwd = 2)
as.numeric works to me
ggplot(data=bmelt)+
geom_line(aes(x=day,y=value,colour=type),size=0.9)+
scale_color_manual(labels = c("Observed","Counterfactual"),values = c("1","2"))+
geom_ribbon(data=ita3,aes(x=day,
y=expcumresponse, ymin=exp.cr.ll,ymax=exp.cr.uu),alpha=0.2) +
labs(title="Italy Confirmed cases",
y ="# Cases ", x = "Date",color="Output")+
geom_vline(xintercept = as.numeric(ymd("2020-03-13")), linetype="dashed",
color = "blue", size=1.5)+
theme_minimal()
code output
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