How to find specified name and its value in JSON-string from Java? [closed]

Question

Let's assume we have the next JSON string:

{      "name" : "John",    "age" : "20",    "address" : "some address",    "someobject" : {        "field" : "value"        } } 

What is the easiest (but still correct, i.e. regular expressions are not acceptable) way to find field age and its value (or determine that there's no field with given name)?

p.s. any open-source libs are ok.

p.s.2: please, don't post links to the libraries - it's not a useful answer. 'Show me the code'(c).

Answer 1

Use a JSON library to parse the string and retrieve the value.

The following very basic example uses the built-in JSON parser from Android.

String jsonString = "{ \"name\" : \"John\", \"age\" : \"20\", \"address\" : \"some address\" }"; JSONObject jsonObject = new JSONObject(jsonString); int age = jsonObject.getInt("age"); 

More advanced JSON libraries, such as jackson, google-gson, json-io or genson, allow you to convert JSON objects to Java objects directly.

Answer 2

Gson allows for one of the simplest possible solutions. Compared to similar APIs like Jackson or svenson, Gson by default doesn't even need the unused JSON elements to have bindings available in the Java structure. Specific to the question asked, here's a working solution.

import com.google.gson.Gson;  public class Foo {   static String jsonInput =      "{" +        "\"name\":\"John\"," +        "\"age\":\"20\"," +        "\"address\":\"some address\"," +        "\"someobject\":" +       "{" +          "\"field\":\"value\"" +        "}" +      "}";    String age;    public static void main(String[] args) throws Exception   {     Gson gson = new Gson();     Foo thing = gson.fromJson(jsonInput, Foo.class);     if (thing.age != null)     {       System.out.println("age is " + thing.age);     }     else     {       System.out.println("age element not present or value is null");     }   } }