I'm using SQL Server 2008. I have a table
Customers
customer_number int
field1 varchar
field2 varchar
field3 varchar
field4 varchar
... and a lot more columns, that don't matter for my queries.
Column customer_number is pk. I'm trying to find duplicate values and some differences between them.
Please, help me to find all rows that have same
1) field1, field2, field3, field4
2) only 3 columns are equal and one of them isn't (except rows from list 1)
3) only 2 columns equal and two of them aren't (except rows from list 1 and list 2)
In the end, I'll have 3 tables with this results and additional groupId, which will be same for a group of similar (For example, for 3 column equals, rows that have 3 same columns equal will be a separate group)
Thank you.
One way to find duplicate records from the table is the GROUP BY statement. The GROUP BY statement in SQL is used to arrange identical data into groups with the help of some functions. i.e if a particular column has the same values in different rows then it will arrange these rows in a group.
1. Using the Distinct Keyword to eliminate duplicate values and count their occurences from the Query results. We can use the Distinct keyword to fetch the unique records from our database. This way we can view the unique results from our database.
Here's a handy query for finding duplicates in a table. Suppose you want to find all email addresses in a table that exist more than once:
SELECT email, COUNT(email) AS NumOccurrences
FROM users
GROUP BY email
HAVING ( COUNT(email) > 1 )
You could also use this technique to find rows that occur exactly once:
SELECT email
FROM users
GROUP BY email
HAVING ( COUNT(email) = 1 )
The easiest would probably be to write a stored procedure to iterate over each group of customers with duplicates and insert the matching ones per group number respectively.
However, I've thought about it and you can probably do this with a subquery. Hopefully I haven't made it more complicated than it ought to, but this should get you what you're looking for for the first table of duplicates (all four fields). Note that this is untested, so it might need a little tweaking.
Basically, it gets each group of fields where there are duplicates, a group number for each, then gets all customers with those fields and assigns the same group number.
INSERT INTO FourFieldsDuplicates(group_no, customer_no)
SELECT Groups.group_no, custs.customer_no
FROM (SELECT ROW_NUMBER() OVER(ORDER BY c.field1) AS group_no,
c.field1, c.field2, c.field3, c.field4
FROM Customers c
GROUP BY c.field1, c.field2, c.field3, c.field4
HAVING COUNT(*) > 1) Groups
INNER JOIN Customers custs ON custs.field1 = Groups.field1
AND custs.field2 = Groups.field2
AND custs.field3 = Groups.field3
AND custs.field4 = Groups.field4
The other ones are a bit more complicated, however as you'll need to expand out the possibilities. The three-field groups would then be:
INSERT INTO ThreeFieldsDuplicates(group_no, customer_no)
SELECT Groups.group_no, custs.customer_no
FROM (SELECT ROW_NUMBER() OVER(ORDER BY GroupsInner.field1) AS group_no,
GroupsInner.field1, GroupsInner.field2,
GroupsInner.field3, GroupsInner.field4
FROM (SELECT c.field1, c.field2, c.field3, NULL AS field4
FROM Customers c
WHERE NOT EXISTS(SELECT d.customer_no
FROM FourFieldsDuplicates d
WHERE d.customer_no = c.customer_no)
GROUP BY c.field1, c.field2, c.field3
UNION ALL
SELECT c.field1, c.field2, NULL AS field3, c.field4
FROM Customers c
WHERE NOT EXISTS(SELECT d.customer_no
FROM FourFieldsDuplicates d
WHERE d.customer_no = c.customer_no)
GROUP BY c.field1, c.field2, c.field4
UNION ALL
SELECT c.field1, NULL AS field2, c.field3, c.field4
FROM Customers c
WHERE NOT EXISTS(SELECT d.customer_no
FROM FourFieldsDuplicates d
WHERE d.customer_no = c.customer_no)
GROUP BY c.field1, c.field3, c.field4
UNION ALL
SELECT NULL AS field1, c.field2, c.field3, c.field4
FROM Customers c
WHERE NOT EXISTS(SELECT d.customer_no
FROM FourFieldsDuplicates d
WHERE d.customer_no = c.customer_no)
GROUP BY c.field2, c.field3, c.field4) GroupsInner
GROUP BY GroupsInner.field1, GroupsInner.field2,
GroupsInner.field3, GroupsInner.field4
HAVING COUNT(*) > 1) Groups
INNER JOIN Customers custs ON (Groups.field1 IS NULL OR custs.field1 = Groups.field1)
AND (Groups.field2 IS NULL OR custs.field2 = Groups.field2)
AND (Groups.field3 IS NULL OR custs.field3 = Groups.field3)
AND (Groups.field4 IS NULL OR custs.field4 = Groups.field4)
Hopefully this produces the right results and I'll leave the last one as an exercise. :-D
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