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How to find city temperature by longitude and latitude in android? [closed]

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android

how to find city temperature by longitude and latitude.... Does anyone know of a service with an API or a widget that I could use to display weather based on geographical coordinates?

like image 219
Akash Singh Avatar asked Aug 12 '11 09:08

Akash Singh


People also ask

How do I find the latitude and longitude of a device?

getLastKnownLocation(LocationManager. GPS_PROVIDER); double longitude = location. getLongitude(); double latitude = location. getLatitude();


2 Answers

we can find city temp by using this find_Location Class. in which firstly find the city location by use by longitude and latitude in android? And after that use the method SendToUrl to find the temperature by use GoogleXML "http://api.wunderground.com/auto/wui/geo/WXCurrentObXML/index.xml?query="

public void find_Location(Context con)
    {
        Log.d("Find Location", "in find_location");
        this.con=con;
        String location_context = Context.LOCATION_SERVICE;
        locationManager = (LocationManager)con.getSystemService(location_context);

        List<String> providers = locationManager.getProviders(true);
       for (String provider : providers) 
       {
           locationManager.requestLocationUpdates(provider, 1000, 0,new LocationListener()
           {
               public void onLocationChanged(Location location) {}
               public void onProviderDisabled(String provider){}
               public void onProviderEnabled(String provider){}
               public void onStatusChanged(String provider, int status,Bundle  extras){}
           });
           Location location = locationManager.getLastKnownLocation(provider);
           if (location != null)
           {
               latitude = location.getLatitude();
               longitude = location.getLongitude();
               addr=ConvertPointToLocation(latitude,longitude);
                       String temp_c=SendToUrl(addr);

           } 
       }
    }

    public String ConvertPointToLocation(double pointlat,double pointlog) {

        String address = "";
        Geocoder geoCoder = new Geocoder(con,
                Locale.getDefault());
        try {
            List<Address> addresses = geoCoder.getFromLocation(pointlat,pointlog, 1);
            if (addresses.size() > 0) {
                for (int index = 0; index < addresses.get(0)
                        .getMaxAddressLineIndex(); index++)
                    address += addresses.get(0).getAddressLine(index) + " ";
            }
        }
        catch (IOException e) {
            e.printStackTrace();
        }
        return address;
    }  

    private String  SendToUrl(String string) {
        // TODO Auto-generated method stub

          try{
              string=string.replace(" ","%20");

        String queryString="http://api.wunderground.com/auto/wui/geo/WXCurrentObXML/index.xml?query="+string;
        url= new URL(queryString);

        conec= url.openConnection();
        stream = conec.getInputStream();
        xpp = XmlPullParserFactory.newInstance().newPullParser();
        xpp.setInput(stream, null);
        int eventType = xpp.getEventType();
        while(eventType != XmlPullParser.END_DOCUMENT)
        {
              if(eventType == XmlPullParser.START_TAG)
            {String elementName = xpp.getName();
                  if("temp_c".equals(elementName))
                    {
                               int acount=xpp.getAttributeCount();
                   for(int x=0;x<acount;x++) 
            {
            xpp.getAttributeValue(x);          
                        String str=xpp.getAttributeValue(x);
                     return str;
         }  

          }
      }
      eventType = xpp.next();
    }
}
like image 120
Akash Singh Avatar answered Sep 17 '22 12:09

Akash Singh


Google Weather API is not supported now. So the above code will not work now. You can use the following url , pass your current location latitude , longitude and you will get resultant xml from which you can extract the desired info.

http://forecast.weather.gov/MapClick.php?lat=40.78158&lon=-73.96648&FcstType=dwml

like image 21
Abhishek Gahlout Avatar answered Sep 18 '22 12:09

Abhishek Gahlout