How to find all files and separate results by comma on Unix?

Question

I would like to go from the standard find output which is:

path/to/file1.yaml
path/to/file2.yaml
path/to/file3.yaml

To this:

path/to/file1.yaml,path/to/file2.yaml,path/to/file3.yaml

What's the simplest way to do that from the command line?

I have tried these things:

find . -path '*.yaml' | sed -e 's/\s/,/g'
find . -path '*.yaml' -print0 | sed -e 's/ /,/g'

but doesn't seem to work.

Answer 1

Here is one approach for separating the filenames with commas:

find . -path '*.yaml' | tr '\n' ','

If the file names do not contain white space, then another approach is:

IFS=, echo $(find . -path '*.yaml')

In the comments, Kojiro suggests a third approach which preserves whitespace:

find . -path '*.yaml' -print0 | tr '\0' ,

Because newlines and commas are allowed in file names, this format may lead to confusion. This format should only be used if you know that your files are sensibly named.

Answer 2

This will work too :

  find . -path '*.yaml' | paste -s -d ',' -

Answer 3

both python and perl can do it in one line:

python:

find . -path '*.yaml' | python -c 'import sys; print ",".join(sys.stdin.readlines())'

perl:

find . -path '*.yaml' | perl -e 'print join ",", map {chomp;$_} <STDIN>'